8 meters per second and a horizontal component of 49 meters per second. How long will certainly it take the projectile to with the highest suggest in that is path?

The gravitational acceleration competent by the bullet because of the earth"s gravitational force is around equals come 9.81 m/s^2At maximum allude of height, vertical component of velocity equates to to zero since it experiences a stop momentarily before coming back down. Due to the fact that -acceleration=(Final velocity-initial velocity) split by time. Acquisition upwards to it is in positive, time taken= 10s

surfacetoairnewyork.com:

10 seconds

Explanation:

There are many formulas that have the right to be used to calculate time taken, or last velocity, or early velocity, etc.

You are watching: A projectile is fired from a gun near the surface of earth

However, the simplest formula to use in this case would be:

v = u + at (where v= last velocity; u= early stage velocity; a= acceleration; t= time)

At the bullet"s highest possible point, it will certainly not have any kind of vertical velocity, and since we are trying to uncover the time it takes to reach the highest point, we take the final velocity together zero.

Initial velocity was provided as 98 m/s in the upright direction.

Acceleration because of gravity is -9,8 m/s² (negative because of taking the up direction as positive).

Plugging in the values:

t = (v-u) / a

t = (0-98 m/s) / -9,8 m/s²

t = 10 seconds


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See the attachment below for the calculation.

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